Facile oxidation of phenylphosphinic acid to phenylphosphonic acid using [Cu2(μ-O2CCH3)4(H2O)2]: X-ray crystal structures of monomeric [Cu(PhPO3H)2(C5H5N)4]·2CH3OH and [Cu(PhPO3H)2(C5H5N)4]
McCann, M., Murphy, E., Cardin, C. Full text not archived in this repository. It is advisable to refer to the publisher's version if you intend to cite from this work. See Guidance on citing. To link to this item DOI: 10.1016/S0277-5387(00)83649-9 Abstract/SummaryPhenylphosphinic acid (HPhPO2H) is oxidized to phenylphosphonic acid (PhPO3H2) at room temperature using a solution of [Cu2(μ-O2CCH3)4(H2O)2] in pyridine. The phenylphosphonic acid was recovered as the monomeric copper(II) complex [Cu(PhPO3H)2(C5H5N)4]·H2O (1a), and the reaction thought to proceed via a copper(I) intermediate. Recrystallization of 1a from methanol gave [Cu(PhPO3H)2(C5H5N)4]·2CH3OH (1b). The unsolvated complex [Cu(PhPO3H)2(C5H5N)4] (1c) was prepared by refluxing polymeric [Cu(PhPO3)(H2O)] (2) in pyridine. The X-ray crystal structures of 1b and 1c show that in each of these monomeric complexes the copper(II) ion is ligated by four equatorial pyridine molecules and two axial monoanionic phenylphosphonate groups. A cyclic voltammetric study of 1a revealed a quasi-reversible Cu2+/Cu+ couple with E1/2 = +228 mV (vs Ag/AgCl).
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