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Facile oxidation of phenylphosphinic acid to phenylphosphonic acid using [Cu2(μ-O2CCH3)4(H2O)2]: X-ray crystal structures of monomeric [Cu(PhPO3H)2(C5H5N)4]·2CH3OH and [Cu(PhPO3H)2(C5H5N)4]

McCann, M., Murphy, E., Cardin, C. ORCID: https://orcid.org/0000-0002-2556-9995 and Convery, M. (1992) Facile oxidation of phenylphosphinic acid to phenylphosphonic acid using [Cu2(μ-O2CCH3)4(H2O)2]: X-ray crystal structures of monomeric [Cu(PhPO3H)2(C5H5N)4]·2CH3OH and [Cu(PhPO3H)2(C5H5N)4]. Polyhedron, 11 (24). pp. 3101-3107. ISSN 0277-5387

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To link to this item DOI: 10.1016/S0277-5387(00)83649-9

Abstract/Summary

Phenylphosphinic acid (HPhPO2H) is oxidized to phenylphosphonic acid (PhPO3H2) at room temperature using a solution of [Cu2(μ-O2CCH3)4(H2O)2] in pyridine. The phenylphosphonic acid was recovered as the monomeric copper(II) complex [Cu(PhPO3H)2(C5H5N)4]·H2O (1a), and the reaction thought to proceed via a copper(I) intermediate. Recrystallization of 1a from methanol gave [Cu(PhPO3H)2(C5H5N)4]·2CH3OH (1b). The unsolvated complex [Cu(PhPO3H)2(C5H5N)4] (1c) was prepared by refluxing polymeric [Cu(PhPO3)(H2O)] (2) in pyridine. The X-ray crystal structures of 1b and 1c show that in each of these monomeric complexes the copper(II) ion is ligated by four equatorial pyridine molecules and two axial monoanionic phenylphosphonate groups. A cyclic voltammetric study of 1a revealed a quasi-reversible Cu2+/Cu+ couple with E1/2 = +228 mV (vs Ag/AgCl).

Item Type:Article
Refereed:Yes
Divisions:Life Sciences > School of Chemistry, Food and Pharmacy > Department of Chemistry
ID Code:23804
Publisher:Elsevier

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